Cuantos gramos de sulfato de cobre (CuSO4), disueltos en 25 ml de agua , se necesitan para preparar 100 ml de disolución a 80 % en masa?

Mass of CuSO₄ you need to prepare a 80% (w/w) solution in 25mL of water is 100g

Explanation:

A solution of 80% (w/w) means you have 80g of solute (CuSO₄, in this case) per 100g of solution (CuSO₄ + water)

Density of water is 1.00g/mL. That means you have 25g of water, thus, to prepare a solution of 80% in mass you need:

80% = Mass CuSO₄ / (Mass CuSO₄ + 25g)

20g + 0.8Mass CuSO₄ = Mass CuSO₄

20g = 0.2 Mass CuSO₄

100g = Mass CuSO₄

Thus, mass of CuSO₄ you need to prepare a 80% (w/w) solution in 25mL of water is 100g

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

c, liquids evaporate, creating a gas