In a titration, 25.0 ml of 0.500 m khp is titrated to the equivalence point with naoh. the final solution volume is 53.5 ml. what is the value of m2 for the reaction?

0.439 m

0.500 m

0.234 m

1.07 m

Answer : The concentration of the NaOH is, 0.234 M

Explanation :

Using neutralization law,

where,

= basicity of an acid = 1

= acidity of a base = 1

= concentration of KHP = 0.500 M

= concentration of NaOH = ?

= volume of KHP = 25 ml

= volume of NaOH = 53.5 ml

Now put all the given values in the above law, we get the concentration of the NaOH.

Therefore, the concentration of the NaOH is, 0.234 M