(5 points) In the lab you find four bags; each contains 5.00 g of a different gas at STP. The gases are O2, C2H6, CO2, and Ne. Which bag has the largest volume? a O2 b C2H6 c CO2 d Ne

Option D. Ne

Explanation:

Step 1

Data obtained from the question:

Mass of O2 = 5g

Mass of C2H6 = 5g

Mass of CO2 = 5g

Mass of Ne = 5g

Step 2:

At this stage we'll determine the mole of each gas. This is illustrated below:

For O2:

Mass of O2 = 5g

Molar Mass of O2 = 16x2 = 32g/mol

Number of mole = Mass/Molar Mass

Number of mole of O2 = 5/32

Number of mole of O2 = 0.156 mole

For C2H6

Mass of C2H6 = 5g

Molar Mass of C2H6 = (12x2) + (6x1) = 24 + 6 = 30g/mol

Number of mole = Mass/Molar Mass

Number of mole of C2H6 = 5/30

Number of mole of C2H6 = 0.167 mole

For CO2:

Mass of CO2 = 5g

Molar Mass of CO2 = 12 + (16x2) = 12 + 32 = 44g/mol

Number of mole = Mass/Molar Mass

Number of mole of CO2 = 5/44

Number of mole of CO2 = 0.114 mole

For Ne:

Mass of Ne = 5g

Molar Mass of Ne = 20g/mol

Number of mole = Mass/Molar Mass

Number of mole of Ne = 5/20

Number of mole of Ne = 0.25 mole

Step 3:

Determination of the volume occupied by each gas.

This is illustrated below:

1 mole of a gas occupy 22.4L at stp.

For O2:

0.156 mole will occupy = 0.156 x 22.4 = 3.49 L

For C2H6:

0.167 mole will occupy = 0.167 x 22.4 = 3.74L

For CO2:

0.114 mole will occupy = 0.114 x 22.4 = 2.55L

For Ne:

0.25 mole will occupy = 0.25 x 22.4 = 5.6L

Considering the calculations made above, it is evident that Ne has the largest volume