How many molecules of nitrogen gas are in 22.4 l?

a. 6.022 × 10^22

b. 6.022 × 10^23

c. 6.022 × 10^24

d. 6.022 × 10^25

Based on the constants and the different standard conditions, each mole of any gas will occupy a volume of 22.4 L with the assumption that the gas is an ideal gas. From the given, there is 1 mole of nitrogen gas. We multiply this number of moles by the Avogadro's number, obtaining 6.022 x 10^23. Thus, the answer is letter B.