Calculate the molarity of the following solution: 2.30 moles of sodium chloride in 0.452 liters of solution.
A.1.04 M
B.5.01 M
C.0.197M

B = 5.01M

Explanation:

n= 2.3mol, V= 0.452L, C=?

Applying n= CV

2.3= C× 0.452

C= 5.08M

explanation:

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yes

explanation:

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