Given the reactant side of the total ionic equation for the neutralization reaction of lithium hydroxide (lioh) with hydrochloric acid (hcl), write the total ionic equation (also known as the complete ionic equation) by entering both the reactant and the product species, separated by the reaction arrow.

li+(aq)+oh−(aq)+h+(aq)+cl−(aq)→

be sure to include the charges on the ionic species and the physical state of all the reactant and product species.

Li⁺ (aq) + OH⁻ (aq) + H⁺ (aq) + Cl⁻(aq) → Li⁺ (aq) + Cl⁻ (aq) + H₂O(l)

Explanation:


1) Combine the cation Li⁺ (aq) with the anion Cl- (aq) to form LiCl(s).

LiCl is a solid soluble substance, a typical ionic compound. So, it will reamain as separate ions in the product side: Li⁺ + CL⁻

2) Combine the anion OH⁻ with the cation H⁺ to form H₂O(l).

Since, the ionization of H₂O is low, it will remain as liquid in the product side: H₂O(l)

3) Finally, you can wirte the total ionic equation:

Li⁺ (aq) + OH⁻ (aq) + H⁺ (aq) + Cl⁻(aq) → Li⁺ (aq) + Cl⁻ (aq) + H₂O(l)

Most likely a is the answer - because  you generate   38 atp's but also consume an atp.   each atp gives approx. less than 4 kcal so probably a is the closest answer.