The chemical reaction represented by the following balanced chemical equation takes place in aqueous
solution: MnO4 + 5 Fe2+8H - Mn2 + 5 Fe3+ 4H2O
When the disappearance of the permanganate ion, MnO4, is monitored, the rate of reaction for the
consumption of the ion is 4.0x10^2 mol/L. s. Calculate the reaction rate for all other reactants and products.

Fe²⁺ = 80mol/Ls

H⁺ = 50mol/Ls

Mn²⁺ = 4.0x10²mol/Ls

Fe³⁺ = 80mol/Ls

H₂O = 1.0x10²mol/Ls

Explanation:

Based on the reaction:

MnO₄⁻ + 5 Fe²⁺ + 8H⁺ → Mn²⁺ + 5 Fe³⁺ +  4H₂O

Where 1 mole of permangante with 5 moles of Fe²⁺ and 8 moles of H⁺ produce 1 mole Mn²⁺, 5 of Fe³⁺ and  4 of H₂O

If the diappearence of 1 mole has a rate of 4.0x10²mol/Ls, disappearence of 5 moles of Fe²⁺ and 8 moles of H⁺ have a rate of:

Fe²⁺ = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 5 moles of Fe²⁺) = 80mol/Ls

H⁺ = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 8 moles of H⁺) = 50mol/Ls

And rate of appearance of 1 mole Mn²⁺, 5 of Fe³⁺ and  4 of H₂O are:

Mn²⁺ = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 1 moles of Mn²⁺) = 4.0x10²mol/Ls

Fe³⁺ = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 5 moles of Fe³⁺) = 80mol/Ls

H₂O = 1 mole MnO₄⁻ × ( 4.0x10²mol/Ls / 4 moles of H₂O) = 1.0x10²mol/Ls

1 is the answer to this problem