Calculate the molarity of an aqueous solution of NaOH if its pH is measured and found to be 12.00.

Explanation:

pH = 12

[H⁺] = 10⁻¹²

[OH⁻¹ ] [H⁺] = 10⁻¹⁴

[OH⁻¹ ] = 10⁻²

NaOH = Na⁺¹ + OH⁻¹

NaOH is a strong base so it dissociates 100%

[OH⁻¹ ] = 10⁻²

molarity of NaOH = 10⁻² M

= .01 M .

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