A sample of a gas has a volume if 852mL at 288K. What temperature did s necessary for the gas to have a volume of 945mL?

The answer to your question is T2 = 319.4°K  

Explanation:

Data

Volume 1 = V1 = 852 ml

Temperature 1 = T1 = 288°K

Volume 2 = V2 = 945 ml

Temperature 2 = T2 = ?

Process

To solve this problem, use Charles' law.

            V1/T1 = V2/T2

-Solve for T2

            T2 = V2T1/V1

-Substitution

            T2 = (945 x 288) / 852

-Simplification

            T2 = 272160 / 852

-Result

            T2 = 319.4°K  

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explanation:

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.