If a sample of NH3 gas at 689,1 mmHg has a volume of 607 2 mL and the presure is
changed to 560,8 mmHg, then what will be the new volume of the NH3 gas, in militers. Be
sure to round to the correct sig digs,

The answer to your question is V2 = 746.1 ml

Explanation:

Data

Pressure 1 = P1 = 689.1 mmHg

Volume 1 = V1 = 607.2 ml

Pressure 2 = P2 = 560.8 mmHg

Volume 2 = V2 = ?

Process

To solve this problem use Boyle's law

              P1V1 = P2V2

-Solve for V2

              V2 = P1V1/P2

-Substitution

               V2 = (689.1 x 607.2) / 560.8

-Simplification

                V2 = 746.1 ml

the temperature of the gas, in k, not celsius.