Be sure to answer all parts. From the following reaction and data, find (a) S o of SOCl2 (b) T at which the reaction becomes nonspontaneous SO3(g) + SCl2(l) → SOCl2(l) + SO2(g) ΔG o rxn = −75.2 kJ SO3(g) SCl2(l) SOCl2(l) SO2(g) ΔH o f (kJ/mol) −396 −50.0 −245.6 −296.8 S o (J/mol · K) 256.7 184 − 248.1

Explanation:

Hrxn = -245.6-296.8+396+50.0 = -96.4 (kJ/mol)

Since Grxn = Hrxn - T*Srxn, where T = 298.15K, we have:

Srxn = (Hrxn - Grxn)/T = (-96.4+75.2)× 1000÷298.15 = -71.1 (j/K mol)

Since: Srxn = Sf (SO2) + Sf (SOCl2)- Sf (SO3) - Sf (SCl2),

or: -71.1 = 248.1 + Sf (SOCl2) - 256.7-184,

Sf (SOCl2) = 256.7+184-71.1-248.1 = 121.5 (J/mol*k)

In order to find T such that Grxn = Hrxn - T*Srxn >= 0. since Hrxn is negative and Srxn is positive, Grxn will always be less than zero. Therefore there won't be a temperature point at which the reaction is going to be non-spontaenous

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

16

explanation:

the marks go by 4s