Calculate the mass of solid CuSO4∙5H2O (±0.1 g) needed to prepare 25.00 mL of 0.10 M Cu2+ solution. When calculating the molar mass, include the full formula of the CuSO4∙5H2O (s) – its formula is called "copper (II) sulfate pentahydrate" and includes five water molecules.

The mass of solid CuSO4∙5H2O is 0.624 grams

Explanation:

Step 1: Data given

Volume of Cu^2+ = 25.00 mL = 0.025L

Molarity of Cu^2+ = 0.10 M

Molar mass of CuSO4 *5H2O = 249.68 g/mol

Step 2: Calculate moles Cu^2+

Moles Cu^2+ = molarity Cu^2+ * volume Cu^2+

Moles Cu^2+ = 0.10 M * 0.025 L

Moles Cu^2+ = 0.0025 moles

Step 3: Calculate moles CuSO4 *5H2O needed

For 1 mol CuSO4 *5H2O we have 1 mol Cu^2+

For 0.0025 moles Cu^2+ we'll have 0.0025 moles CuSO4 *5H2O

Step 4: Calculate mass CuSO4 *5H2O

Mass CuSO4 *5H2O = moles / molar mass

Mass CuSO4 *5H2O = 0.0025 moles / 249.68 g/mol

Mass CuSO4 *5H2O = 0.624 grams

The mass of solid CuSO4∙5H2O is 0.624 grams

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because it does not have the potential to be entirely used up