How much 0.05 M of magnesium chlorate solution can be made by diluting 250 mL of 10 M HCL?
Group of answer choices

1.25 L

50L

50 litres of magnesium chlorate solution can be made by diluting 250 ml of 10 M HCl.

The correct option is 2.

Explanation:

Data given:

Molarity of magnesium chlorate M1 = 0.05 M

volume of the magnesium chlorate V1 = ?

Molarity of the HCl solution = 10 M

volume of the HCl solution = 250 ml or 0.25 litres

the formula used is for dilution

M1V1 = M2V2

rearranging the equation to get the volume of magnesium chlorate solution,

V1 =

putting the values in the equation:

V1 =

V1 = 50 LITRES

thus the 0.05 M of the magnesium chlorate solution can be made by diluting the given solution with 50 litres.

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.