Chemistry, 24.04.2020 20:29 aris35

1. Zinc metal reacts with 100 mL of 6.00 M H2SO4. How many grams of Zinc Sulfate are produced and how many liters of Hydrogen gas would be released?

2.A 211 g sample of BaCO3 is reacted with HNO3. Assuming the acid is present is excess, what mass and volume of CO2 gas will be produced?

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Answer from: iamasia06

1. 96.882 grams of Zinc Sulfate are produced and 0.0012 litres of hydrogen is gas formed.

2 . 46.65 grams is the mass of carbon dioxide gas formed and its volume is 23.74 litres.

Explanation:

1) Data given:

volume of Sulphuric acid = 100 ml or 0.1 litre

molarity of sulphuric acid = 6M , number of moles of sulphuric acid = 0.6 moles

number of moles = molarity x volume

6 x 0.1

number of moles = 0.6

Zinc sulphate formed =?

hydrogen gas released =?

balanced chemical reaction

Zn + $H_{2} S_{} O_{4}$ ⇒ ZnS $O_{4}$ +

1 mole of sulphuric acid reacted it formed 1 moles of zinc sulphate and 1 mole of hydrogen gas

so, 0.6 moles of sulphuric acid will give 0.6 moles of zinc sulphate and 0.6 mole of hydrogen gas.

mass = atomic mass x number of moles

mass = 161.47 x 0.6

mass of zinc sulphate formed =96.882 grams

litres of hydrogen gas formed = 0.6 x 2

= 1.2 ml

hence 0.0012 litres of hydroge gas formed

2) Data given:

mass of barium carbonate = 211 grams

atomic mass of barium carbonate = 197.34 grams/mole

balanced reaction:

BaC $O_{3}$ + 2HN $O_{3}$ ⇒ Ba(N $O_{3}$ )2 +C $O_{2}$ + $H_{2}$ O

number of moles of barium carbonate = $\frac{mass}{atomic mass of 1 mole}$

putting values in the equation:

number of moles = $\frac{211}{197.34}$

= 1.06 moles

from the reaction

1 mole of BaCO3 reacted to give 1 mole barium nitrate and 1 mole of carbon dioxide gas

so 1.06 moles of BaCO3 will give 1.06 moles each barium nitrate and carbon dioxide gas

mass = atomic mass x number of moles

mass of carbon dioxide = 1.06 x 44.01

= 46.65 grams

assuming CO2 at STP, we apply ideal gas law

PV = nRT

here T = 273 K, P= 1 atm, R= 0.08201 L atm/mole K

V = $\frac{nRT}{P}$

V = $\frac{1.06 x 0.08201X 273}{1}$

V = 23.74 Litres

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1. Zinc metal reacts with 100 mL of 6.00 M H2SO4. How many grams of Zinc Sulfate are produced and ho...

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