Calculate the standard entropy of reaction for solid sodium reacting with chlorine gas to form solid NaClNaCl at 25 ∘C∘C. 2Na(s)+Cl2(g)→2NaCl(s)2Na(s)+Cl2(g) →2NaCl(s) Substance and State S∘[J/(K⋅mol)]S∘[J/(K⋅mol)] Na(s)Na(s) 51.2 Cl2(g)Cl2(g) 223.0 NaCl(s)NaCl(s) 72.1

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!