500 mL of He at 300 K is heated to 450 K. Find V2

V2 = 0.75 L

Explanation:

assumin ideal gas:

∴ T1 = 300K

∴ V1 = 0.500 L

∴ T2 = 450 K

⇒ V2 = ?

assuming P, n constant:

⇒ PV1 = RT1n

⇒ V1/T1 = Rn/P = K(1)

⇒ V2/T2 = RN/P = K(2)

(1) = (2):

⇒ V1/T1 = V2/T2

⇒ V2 = (V1/T1)T2

⇒ V2 = (0.500 L/300 K)(450 K)

⇒ V2 = 0.75 L

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation:

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72