If you have 39.5g of Fe2O3 how many grams of co are requried to complete reaction

20.8g

Explanation:

1. Balanced chemical equation

Fe₂O₃(s)   +   3CO(g)   →   2Fe(s)   +   3CO₂(g)

2. Convert 39.5g of Fe₂O₃ into moles

#moles = mass in grams / molar massmolar mass of  Fe₂O₃ = 159.69 g/mol#moles = 39.5g / 159.69g/mol = 0.24735 mol

3. Moles of CO

i) Mole ratio

3mol CO / 1 mol Fe₂O₃

ii) Set a proportion

3 mol CO / 1 mol Fe₂O₃ = x / 0.24735 mol Fe₂O₃

     ⇒ x = 0.24735mol Fe₂O₃ × 3mol CO / 1mol Fe₂O₃ = 0.7426 mol CO

4. Grams of CO

molar mass CO: 28.01g/molmass in grams = #moles × molar massmass = 0.7426mol × 28.01g/mol =  20.8g ← answer

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