A gas has a volume of 4.54 L at 1.65 atm and 75. I decrease celsius. At what pressure would the volume of the gas be increased to 5.33 L if the temperature is increased to 103 degrees Celsius?

The answer to your question is P2 = 1.52 atm

Explanation:

Data

Volume 1 = V1 = 4.54 l

Pressure 1 = P1 = 1.65 atm

Temperature 1 = T1 = 75°C

Volume 2= V2 = 5.33 l

Pressure 2 = P2 = ?

Temperature 2 = 103°C

Process

1.- Convert temperature to °K

Temperature 1 = 75 + 273 = 348°K

Temperature 2 = 103 + 273 = 376°K

2.- Use the combine gas law to find the final pressure

               P1V1/T1 = P2V2/T2

-Solve for P2

               P2 = P1V1T2 / T1V2

-Substitution

               P2 = (1.65 x 4.54 x 376) / (348 x 5.33)

-Simplification

               P2 = 2816.62 / 1854.84

-Result

              P2 = 1.52 atm

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

fe 55.85 g/mol and h2o 18.02 g/mol.