23 ml of oxygen collected over water and has a pressure of 636 mmhg at 23 c. what is the pressure of the dry gas at stp

Answer : The pressure of the dry gas at stp is, 0.602 mmHg

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 636 mmHg

= final pressure of gas = ?

= initial volume of gas = 23 mL = 0.023 L

= final volume of gas at STP = 22.4 L

= initial temperature of gas =

= final temperature of gas at STP =

Now put all the given values in the above equation, we get:

Therefore, the pressure of the dry gas at stp is, 0.602 mmHg