The dehydrogenation of benzyl alcohol to make the flavoring agent benzaldehyde is an equilibrium process described by the equation: C6H5CH2OH(g) ⇆ C6H5CHO(g) + H2(g) At 523 K, the value of its equilibrium constant is K = 0.558. (a) Suppose that 1.20 g of benzyl alcohol is placed into a 2.00 L vessel and heated to 523 K. What is the partial pressure of benzaldehyde when equilibrium is attained? (b) What fraction of benzyl alcohol is dissociated into products at equilibrium?

pC6H5CHO = 0.180 atm

Fraction dissociated = 0.756

Explanation:

Step 1: Data given

Temperature = 523 K

the value of its equilibrium constant is K = 0.558

Mass of benzyl alcohol = 1.20 grams

Molar mass of benzyl alcohol = 108.14 g/mol

Volume = 2.00 L

heated to 523 K

Step 2: The balanced equation

C6H5CH2OH(g) ⇆ C6H5CHO(g) + H2(g)

Step 3: Calculate moles benzyl alcohol

Moles benzyl alcohol = Mass / molar mass

Moles benzyl alcohol = 1.20 grams / 108.14 g/mol

Moles benzyl alcC6H5CH2OHohol = 0.0111 moles

Step 4: Initial moles

Moles C6H5CH2OH = 0.0111 moles

Moles C6H5CHO = 0 moles

Moles H2O = 0 moles

Step 5:  moles at the equilibrium

Moles C6H5CH2OH = 0.0111 - X moles

Moles C6H5CHO = X moles

Moles H2O = X moles

Step 6: Calculate the total number of moles at equilibrium

Total number of moles = (0.0111 - X moles) + X moles + X moles

Total number of moles = 0.0111 + X moles

Step 7: Calculate the total pressure at the equilibrium

p*V = n*R*T

p = (n*R*T) / V

⇒with p = the total pressure at the equilibrium = TO BE DETERMINED

⇒with n = the total number of moles = 0.0111 + X moles

⇒with R = the gas constant = 0.08206 L*atm / mol * K

⇒with T = the temperature = 523 K

⇒with V = the volume of the vessel = 2.00 L

p = (0.0111 - X moles ) * 0.08206*523 / 2.00

p = 21.46(0.0111 - X moles)

Step 8: Define the equilibrium constant K

K = 0.558 =  (pC6H5CHO)*(pH2) / (pC6H5CH2OH)

0.558 = (X / (0.0111 + X)*P)²  /  ((0.0111-X)/(0.0111+X)*P)

0.558 = (X²(21.46 * (0.0111+X))) / ((0.0111 + X) (0.0111-X))

X = 0.00839

Step 9: Calculate the equilibrium partial pressure

pC6H5CHO = X / (0.0111 + X)  * (21.46 * (0.0111 +X))

pC6H5CHO = 0.180 atm

Step 10: What fraction of benzyl alcohol is dissociated into products at equilibrium?

Fraction dissociated = Δn / n°

Fraction dissociated = X / 0.0111

Fraction dissociated = 0.00839 / 0.0111

Fraction dissociated = 0.756

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

the answer is c

tell me if wrong