The heat of vaporization Δ1, of toluene (C6H5CH3) is 38.1 kJ/mol. Calculate the change in entropy AS when 207. g of toluene boils at 1 10.6 °C. Be sure your answer contains a unit symbol. Round your answer to 3 significant digits.

The change in entropy change when 207 g of toluene boils at is 223 .

Explanation:

It is given that mass of toulene is 207 g and its molar mass is 92.14 g/mol. So, its moles will be calculated as follows.

     No. of moles =

                           =

                           = 2.25 moles

As we are given that heat of vaporization for 1 mol is 38.1 kJ/mol. So, heat of vaporization for 2.25 moles will be calculated as follows.

            = 85.725 KJ

Now, we know that the relation between enthalpy change and entropy change is as follows.

                        =

                        = 0.223

or,                     = 223         (as 1 kJ = 1000 J)

Thus, we can conclude that the change in entropy change when 207 g of toluene boils at is 223 .

i do not get it   at all