What is the concentration of a nitiric acid (HNO3) solution if 100.0ml of 0.50M NaOH are needed to neutralize 40.0ml of the nitric acid solution?

Answer 0,36 M

Hello!

The general chemical equation for the neutralization of an acid HA with NaOH is the following:

HA(aq) + NaOH(aq) → NaA(aq) + H₂O(l)

For determining the concentration of the acid solution, we can use the equation shown below:

So, the concentration of the Acid is 0,36 M

Have a nice day

Explanation:

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"