Chemistry, 21.04.2020 03:09 lorenacollazo
The empirical formula of a compound of iron (Mg) and sulfur (S) was determined using the following data. A sample of Mg was weighed into a crucible and covered with finely powdered S. The crucible was covered and heated to allow the Fe and S to react. Additional heating burned off all unreacted S. The crucible was then cooled and weighed. The following data was collected. The molecular weight of Mg and S is 24.305 g/mol and 32.065 g/mol respectively. mass of crucible and cover = 27.631 grams mass of crucible, cover and Mg = 33.709 grams mass of crucible, cover, and the compound formed 41.725 grams
Calculate the number of moles Mg and reacted and what is the empirical formula of the compound.
A. 0.25, 0.25, MgS
B. 0.20,0.30, Mg2S3
C. 0.15,0.35, Mg1S3
D. 0.45, 0.25, MgS2
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The empirical formula of a compound of iron (Mg) and sulfur (S) was determined using the following d...
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