How many moles of MgCl2 are contained in 261.5 mL of a 0.005 M MgCl2 solution? Please show your work.

The answer for the following problem is mentioned below.

Explanation:

Molarity:

The no of moles of moles present in one litre of the solution is called molarity

Given:

molarity of magnesium chloride (m) = 0.005 M

volume of magnesium chloride solution (V) = 261.5 ml

To find:

no of moles of magnesium chloride solution (n)

We know;

molarity =

m =  

where;

m represents the molarity of the magnesium chloride solution

n represents the no of moles of magnesium chloride solution

V represents the volume of magnesium chloride solution

So;

0.005 =

n = 0.005 × 261.5

n = 1.3075 moles

Therefore the no of moles in the magnesium chloride solution is 1.3075 moles.