A 50 gram object with a specific heat of 0.3825 J/g*C releases 4593 joules of heat.

If the initial temperature was 235.16C, calculate the final temperature.

475.26°C

Explanation:

Given parameters:

Mass of object = 50g

Specific heat  = 0.3825J/g°C

Quantity of heat  = 4593Joules

Initial temperature  = 235.16°C

Unknown:

Final temperature = ?

Solution:

The quantity of heat absorbed by a body is a function of the mass, specific heat capacity and temperature change the body undergoes.

Mathematically, this relationship is given as;

              H  = m c Ф

where H is the quantity of heat

           m is the mass of the body

            c is the specific heat capacity

            Ф is the temperature difference

Ф  = final temperature - initial temperature

  Since we are solving for final temperature, let us substitute for other given parameters;

    H  =  m c ( final temperature - initial temperature)

       4593  = 50 x 0.3825 x (F  - 235.16)

       F - 235.16  = 240.1

             F  = 240.1 + 235.16 = 475.26°C

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.