How many moles are present in 4.7 liters of Argon gas at STP?

The answer for the following problems is mentioned below.

Explanation:

Mole:

The mass of a substance containing the same number of fundamental units as there are atoms in exactly 12.000 g of .

Given:

volume (v) = 4.7 litres

Volume of argon at STP conditions = 22.4 litres

To find:

volume of argon at STP conditions

We know;

n =

where;

n represents the no of moles

v represents the volume of the argon

V represents the volume of argon at STP

volume of the argon at STP conditions is 22.4 litres

So;

n =

n = 0.20 moles

Therefore the number of moles present in Argon is 0.20 moles.

if two electrons have the same n, the same ℓ, and the same ml, then they are in the same orbital. the pauli exclusion principle states that no two identical fermions (a fancy word for electrons and other subatomic particles like electrons) may occupy the same quantum state in an atom simultaneously.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j