Based on the chart, determine the identity of a substance that increases in temperature by 11.4oC when 1250J of energy are added to a 55g sample.
Substance Specific Heat (J/g oC)
Lithium 3.56
Vegetable Oil 1.99
Air 1.02
Iron 0.444
Sand 0.290
Gold 0.129

Salt

Air

Lithium

Vegetable Oil

LIthium vegetable oil

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in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm