How many moles of H2SO4 are present in 0.500 L of a 0.150 M H2SO4 solution?

0.075

Explanation:

(concentration in molarity)(volume in liter) = answer

0.15 mol/L *0.500L = 0.075 mol

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally