Calculate the volume occupied by 32.0 g of O2 gas, the pressure of the O2 gas is 78.5 kPa at 25°C.

The answer to your question is V = 63.5 l

Explanation:

Data

Volume = ?

mass of O₂ = 32 g

Pressure = 78.5 kPa

Temperature = 25°C

Ideal gas constant = 0.082 atm l/ mol°K

Process

1.- Convert temperature to °K

Temperature = 25 + 273 = 298°K

2.- Write the Ideal gas formula

                PV = nRT

-Solve for Volume (V)

                V = nRT/P

3.- Calculate the number of moles

               16 g 1 mol

               32 g x

                 x = (32 x 1) / 16

                 x = 2 moles

4.- Convert the pressure to atm

                1 atm 101.325 kPa

                x         78.5 kPa

                  x = (78.5 x 1) / 101.325

                  x = 0.77 atm

5.- Substitute values

                V = (2 x 0.082 x 298) / 0.77

6.- Simplification

                V = 48.87 / .77

7.- Result

                V = 63.5 l

lol for the pointsss

a electronegativity decreases beacuse the size of nucleus is bigger.