An air mattress is filled with 0.55 moles of air. The air inside the mattress has a temperature of 295 K and a gauge pressure of 3.5 kilopascals. What is the volume of the air mattress?

385.4132857

Explanation:

Using the equation, PV=nRT, you can solve this problem.

P= 3.5 kPa      V=?    n= 0.55 moles of air     T= 295K    R= 8.314 (L kPa/mol K)

We use the constant rate of 8.314 because we are using kilopascals in this problem.

Using simple algebra we get-

V = (0.55 moles)(8.314 L kPa/mol k)(295 K) / 3.5 kPa

Using the calculator, we would get the answer of 385.4132857 L.

And whatever the significant figure is asked for, for example, 3 significant figures: the answer would be 385 liters.

relative humidity is a measure of the amount of moisture in the air relative to the total amount of moisture the air can hold.

so d

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"