Determine the standard cell potential (Ecell0 ) and balanced equation for the voltaic cell:
MnO4-(aq)+I-(aq) → I2(aq)+ Mn2+(aq)
where:
MnO4-+5H+(aq)+5e+→ Mn2+(aq)+4H2O(l): Ered0 =+1.51V.
I2(s)+2e-→2I-(aq): Ered0 =+0.54 V.
A) 16H+(aq)+2MnO4-(aq)+10I-(aq)→5I2(aq )+2Mn2+(aq)+8H2O(l):
Ecell0 = -0.97 V.
B) 16H+(aq)+2MnO4-(aq)+10I-(aq)→5I2(aq )+2Mn2+(aq)+8H2O(l):
Ecell0 = -2.05 V.
C) 16H+(aq)+2MnO4-(aq)+10I-(aq)→5I2(aq )+2Mn2+(aq)+8H2O(l):
Ecell0 = +0.97 V.
D) 8H+(aq)+2MnO4-(aq)+10I-(aq)→5I2(aq) +2Mn2+(aq)+8H2O(l):
Ecell0 = +0.97 V.

C

Explanation: This is what my mastering said

16H+(aq)+2MnO4-(aq)+10I-(aq)→5I2(aq)+2Mn2+(aq)+8H2O(l):

Ecell0 = +0.97 V.

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.