student has a mixture of salt (NaCl) and sugar (C12,H22O11). To determine the percent composition, the student measures out 5.84 g of the mixture and dissolves the sample in 100.0 mL of water. The student knows aqueous NaCl will react with aqueous silver nitrate (AgNO3) to form solid silver chloride (AgCl). The student determines the sugar will not react with silver nitrate. How many mL of 1.0 M AgNO3 will be required to precipitate 5.84g AgCl?

Explanation:

All the Ag in the 5.84 g of AgCl precipitate is in the 1.0M solution of AgNO₃.

1. Determine the number of moles of AgCl in 5.84g:

2. The number of moles of Ag is equal to the number of moles of AgCl, since the ratio of atoms is 1 : 1.

3. The number of moles of AgNO₃ is equal to the number of moles of Ag because the ratio is 1 : 1 too.

4. The molarity formula allows you to determine the volume of AgNO₃ solution that contains 0.04074798 moles of AgNO₃

Convert to mililiter:

Round to two significant figures: 41 ml ← answer

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