What mass of CuSO4 are needed to prepare 100 mL of a 0.10 M solution? grams

1.596 grams of CuSO4 would be needed to prepare 100 mL of 0.10 M solution.

A 0.10 M solution of CuSO4 contains:

Thus, 0.01 moles of CuSO4 would have an equivalent mass of:

mole = mass/molar mass

            mass = mole x molar mass

                           = 0.01 x 159.6

                              = 1.596 grams

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1.596 grams is the mass of CuSO4  needed to prepare 100 ml solution of 0.1 M solution.

Explanation:

Data given:

Volume of the solution = 100 ml or 0.1 litre

molarity of the solution = 0.10 M

mass of CuS = ?

atomic mass of CuS  = 159.6 grams/mole

The mass will calculated by using the following relations:

number of moles =     equation 1

molarity =                          equation 2

putting the value of number of moles in equation 2

molarity =

mass = molarity x atomic mass x volume

mass = 0.1 x 0.1 x 159.6

         = 1.596 grams

1.596 grams will form 100ml solution 0.1 M