If the concentration of the fluid inside a tree is about 0.15 M greater than the groundwater that bathes the roots, how high will a column of fluid rise in the tree at 19°C? Assume that the density of the fluid is 1.1 . (The density of mercury is 13.6 .) m

The height is

Explanation:

From the question we are told that

           The concentration inside a is tree

           The temperature condition is

          The density of the fluid is  

          The density of mercury is

Generally osmotic pressure experience is mathematically represented as

    Where R is the universal gas constant with a value of R = 00821 L.atm/K/mol

Converting to cm of Mercury

Generally pressure is mathematically represented as

 Now making height the subject

Where pressure is  

        and  Density is

So we have

In meters          h

The fluid column will rise a height of 3720.96 cm

Explanation:

The osmotic pressure is equal:

Where

M = 0.15 M

T = 19ºC = 292 K

Replacing:

The height is:

Where

ρ = 13.6 g/cm³

Replacing: