A calorimeter was filled with 200 g of water. The temperature of the water in the calorimeter dropped from 55.0 °Celsius to 22.6 °Celsius. The specific heat of water is 4.184 J/g°C. Calculate, q, the heat released by the reaction.

Higher temperature = molecules move around faster. and vice versa.

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.

I'm sorry but, is there a list of options?