Chemistry, 15.04.2020 18:01 maisymooch

A solution containing an ionic compound is subjected to the anion and cation confirmation tests performed in this experiment, providing the following results: Addition of silver nitrate: a bright yellow precipitate formed. Flame test: a purple color was observed. Identify the ionic compound and write the chemical reaction that occurs when the ionic compound interacts with the silver nitrate. Identify the spectator ions.

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Answer from: skyvargasov9cad

The ionic compound is KI and when it reacts with AgNO₃ the spectator ions are K⁺ and NO₃⁻.

A solution that contains a cation and an anion is subjected to 2 experiments to confirm their identities.

In the flame test, a purple color is observed. The cation that gives purple is the flame test is potassium.

Upon the addition of silver nitrate, a bright yellow precipitate is formed. The precipitate is AgI, so the anion is iodide.

The ionic compound formed by K⁺ and I⁻ is KI.

The molecular equation for the reaction between AgNO₃ and KI is:

AgNO₃(aq) + KI(aq) ⇒ KNO₃(aq) + AgI(s)

The net ionic equation is:

Ag⁺(aq) + I⁻(aq) ⇒ AgI(s)

The spectator ions, those that don't appear in the net ionic equation, are K⁺ and NO₃⁻.

The ionic compound is KI and when it reacts with AgNO₃ the spectator ions are K⁺ and NO₃⁻.

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Answer from: raerea2005

The spectator ions are K⁺ and NO₃⁻, since these ions do not involve in any reaction.

Explanation:

It is given that a bright yellow precipitate will be formed when the given substance reacts with silver nitrate. Silver nitrate reacts with anion iodide (I⁻) to form yellow precipitate.

In the flame test, if we get purple color then the cation must be Potassium (K⁺).

So if we combine the cation and anion we will get the compound as Potassium Iodide (KI).

K⁺ + I⁻ + Ag⁺ + NO₃⁻ → KNO₃ + AgI (s) ↓

Here Silver and Iodide ions combine to form a precipitate and Potassium and nitrate ions are acting as spectator ions, which do not involve in the reaction.

Answer from: Quest

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Answer from: Quest

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