The combustion of glucose (C6H12O6) in oxygen produces carbon dioxide and water. Which choice correctly expresses the average rate of reaction in terms of the change in concentration of oxygen gas? C6H12O6 (s) + 6 O2 (g) → 6 CO2 (g) + 6 H2O (l)

C6H12O6(s) + 6O2 =6Co2(g) + 6H20(l)

Explanation:

Combustion of glucose is the burning of glucose in the presence of oxidant, oxygen. It an high temperature exothermic reaction, that is heat is given out. A flame is a characteristic that combustion take place. For combustion to take place, the activation energy must be overcome. The combustion of glucose in oxygen to produce carbondioxide and water release 2803KJ per glucose.

the answer to your question is c

it can be observed without changing the identity of the object.

it depends on what substance you're talking about as well as many other factors. in quantum mechanics, the observation of particles affects the observers ability to measure certain properties. for example: you can know the velocity of a particle, but you can't know it's position; or you can know it's position, but not it's velocity. it's like trying to find out where a grain of sand is by throwing other grains of sand at it. once you find out where it is, it's been moved. it's also like trying to find an answer to the question of whether or not a tree falling in a forest makes a sound if nobody is there to hear it. paradoxically, the only way to find out is to be there and hear it.