In pure water, some of the molecules ionize according to the equation H2O→H+ + OH−. The extent of the ionization increases with temperature. A student heats pure water and records the measured pH at 50°C as 6.6. Based on this information, what mathematical relationships gives the pOH pOH of pure water at 50°C?

Answer : The mathematical relationships gives the pOH of pure water at is,

Explanation :

As we are given that the pH at is, 6.6.

Now we have to determine the mathematical relationships gives the pOH of pure water at .

As we know that:

The ionization of water is:

The expression for dissociation constant for water is:

taking logarithm on both side, we get:

Taking negative sign on both side, we get:

As we know that the value of is 14 at 25-50°C.

So,

or,

Therefore, the mathematical relationships gives the pOH of pure water at is,