Chemistry, 15.04.2020 01:35 lillianneal

Consider the following reaction mechanism: Step 1: (CH3)3AuPH3 ↔ (CH3)3Au + PH3 (fast) Step 2: (CH3)3Au → C2H6 + (CH3)Au (slow) Step 3: (CH3)Au + PH3 → (CH3)AuPH3 (fast) What is the balanced equation for the overall reaction?

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Answer from: LUCASEDIE7430

The balanced equation for overall reaction is:

(CH3)3AuPH3 > C2H6 + (CH3)AuPH3

Explanation:

The reaction mechanism is given as follows:

Step 1: (CH3)3AuPH3 ↔ (CH3)3Au + PH3 (fast)

Step 2: (CH3)3Au → C2H6 + (CH3)Au (slow)

Step 3: (CH3)Au + PH3 → (CH3)AuPH3 (fast)

To balance this equation, firstly, we conduct proper atom count for each steps of the reaction mechanism.

It is important to note that for a reaction that involves several steps, the rate law is normally derived from the slow step ( which is step2 from the above mechanism).

Therefore, the balanced chemical equation for the overall reaction is:

(CH3)3AuPH3 > C2H6 + (CH3)AuPH3

Answer from: deandrebryant89

(CH3)3AuPH3 > C2H6 + (CH3)AuPH3

Explanation:

Firstly, to balance this equation, we conduct proper atom count for each steps of the reaction mechanism.

Step 1: (CH3)3AuPH3 ↔ (CH3)3Au + PH3 (fast)

Step 2: (CH3)3Au → C2H6 + (CH3)Au (slow)

Step 3: (CH3)Au + PH3 → (CH3)AuPH3 (fast)

It is important to note that for this reaction that involves several steps, the rate- determining step in the rate law is derived from the slow step which is seen in step2 from the above mechanism.

Thus, the balanced chemical equation for the overall reaction is:

(CH3)3AuPH3 > C2H6 + (CH3)AuPH3

Answer from: Quest

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh $pcl_{3}$ +δh $cl_{2}$ ] - [δh $pcl_{5}$ ]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

Answer from: Quest

just did the assignment and the answer was #1 +2 n

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