A gas has a volume of 5.00 L at 20.0oC. If the gas is compressed to 4.0 L, what is the new temperature of the gas in Kelvin?

234.4K

Explanation:

Given that,

Original volume of gas (V1) = 5.00 L

Original temperature of gas (T1) = 20.0°C

[Convert 20.0°C to Kelvin by adding 273

20.0°C + 273 = 293K]

New volume of gas (V2) = 4.0L

New temperature of gas (T2) = ?

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

5.00L/293K = 4.0L/T2

To get the value of T2, cross multiply

5.00L x T2 = 293K x 4.0L

5.00L•T2 = 1172L•K

Divide both sides by 5.00L

5.00L•T2/5.00L = 1172L•K/5.00L

T2 = 234.4K

Thus, the new temperature of the gas is 234.4 Kelvin

idk

explanation:

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.