Consider the following reaction: 2CH2Cl2(g) CH4(g) CCl4(g) If 0.203 moles of CH2Cl2(g), 0.323 moles of CH4, and 0.240 moles of CCl4 are at equilibrium in a 15.2 L container at 477 K, the value of the equilibrium constant, Kc, is

Thus value of the equilibrium constant is 1.86

Explanation:

Moles of   at equilibrium= 0.203 mole

Moles of   at equilibrium = 0.323 mole

Moles of   at equilibrium = 0.240mole

Volume of solution = 15.2  L

Equilibrium concentration of =

Equilibrium concentration of =

Equilibrium concentration of =

The given balanced equilibrium reaction is,

The expression for equilibrium constant for this reaction will be,

Now put all the given values in this expression, we get :

Thus value of the equilibrium constant is 1.86