The free energy change for the following reaction at 25 °C, when [Cd2+] = 1.20 M and [Fe2+] = 1.40×10-3 M, is -23.9 kJ: Cd2+(1.20 M) + Fe(s) Cd(s) + Fe2+(1.40×10-3 M) ΔG = -23.9 kJ What is the cell potential for the reaction as written under these conditions? -24.07 V Would this reaction be spontaneous in the forward or the reverse direction?

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