A 0.530 M Ca(OH)2 solution was prepared by dissolving 36.0 grams of Ca(OH)2 in enough water. What is the total volume of the solution thus formed? (4 points) Group of answer choices

The answer to your question is 0.918 l or 918 ml

Explanation:

Data

[Ca(OH)₂] = 0.530 M

mass of Ca(OH)₂ = 36 g

volume = ?

Process

To solve this problem use the formula of Molarity.

Molarity = mass of Ca(OH)₂ / volume

-Solve for Volume

Volume = moles of Ca(OH)₂ / Molarity

-Calculate the moles of Ca(OH)₂

Ca(OH)₂ = 40 + 32 + 2 = 74 g

                 74 g of Ca(OH)₂ 1 mol

                  36 g of Ca(OH)₂  x

                       x = (36 x 1) / 74

                       x = 0.486 moles

-Substitution

Volume = 0.486 / 0.530

-Result = 0.918 l or 918 ml

b.false that your answer