Consider the reaction below.

2 upper I superscript minus (a q) plus upper C l subscript 2 (g) right arrow 2 upper C l minus (a q) plus upper I subscript 2 (a q).

Which half reaction correctly describes the reduction that is taking place?

The reduction half cell reaction is Cl₂(g) +  2e⁻ → 2Cl⁻(aq)

Explanation:

2I⁻(aq) + Cl₂(g) → 2Cl⁻(aq) + I₂(aq)

This is the given balanced red-ox reaction.

Here, we have to find the reduction half reaction, and here the oxidation state of chlorine atom is decreased from 0 to -1, whereas in the oxidation half reaction , the oxidation state of Iodine atom is increased from -1 to 0.

So the reduction half reaction is,

Cl₂(g) +  2e⁻ → 2Cl⁻(aq)

wher is the rest of the question