Question 13
How many particles are present in 400 grams of NaCl?
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There are 4.12 × 10²⁴ particles  present in the 400 grams of sodium chloride.    

Explanation:

We need to find the number of particles present in given mass of sodium chloride.

For that we have to convert the given mass into moles by dividing it with its molar mass, so that it can get converted.

Moles =

        =

       = 6.84 moles

Now this moles is converted into particles by multiplying it with the Avogadro's number of particles as,

Particles present = 6.84 × 6.022 × 10²³

                           = 4.12 × 10²⁴ particles

So there are  4.12 × 10²⁴ particles  present in the given mass of sodium chloride.    

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.