95.8 L of fluorine gas is being held at a temperature of 24.5oC. If the temperature were raised to 46.9 oC, what would the new volume be?

103 litres

Explanation:

Given that,

Original volume of fluorine gas (V1) = 95.8L

Original temperature of fluorine gas (T1) = 24.5°C

[Convert 24.5°C to Kelvin by adding 273

24.5°C + 273 = 297.5K]

New volume of gas (V2) = ?

New temperature of gas (T2) = 46.9°C

[Convert 46.9°C to Kelvin by adding 273

46.9°C + 273 = 319.9K]

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

95.8L/297.5K = V2/319.9K

To get the value of V2, cross multiply

95.8L x 319.9K = 297.5K x V2

30646.42L•K = 297.5K•V2

Divide both sides by 297.5K

30646.42L•K/297.5K = 297.5K•V2/297.5K

103L = V2

Thus, the new volume of fluorine gas will be 103 litres

h let me think

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates