2 Al + 3 H2SO4 --> Al2(SO4)3 + 3 H2
How many grams of hydrogen are produced when 7.5 grams sulfuric acid reacts with plenty of aluminum?

The answer to your question is 0.15 g of H₂

Explanation:

Data

mass of H₂ =

mass of H₂SO₄ = 7.5 g

Balanced chemical reaction

             2Al  +  3H₃SO₄  ⇒   Al₂(SO₄)₃  +  3H₂

Process

1.- Calculate the molar mass of hydrogen and sulfuric acid

H₂ = 3(2) = 6 g

H₂SO₄ = 2 + 32 + (16 x 4) = 3 x 98 g = 294 g

2.- Use proportions to solve this problem

            294 g of H₂SO₄ 6 g of H₂

              7.5 g of H₂SO₄  x

                        x = (7.5 x 6)/294

                        x = 45/294

                        x = 0.15 g of H₂

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