What is the poH of a
4.5 x 10-3 M OH solution?

2.35

Explanation:

pOH is the negative logarithm of hydroxide ion concentration in a solution. Mathematically, pOH is expressed as pOH = -log(OH-)

where (OH-) is the concentration of hydroxide ion.

So, pOH calculations are as follows

pOH = - log(4.5 x 10-3 M)

pOH = - (-2.3468)

pOH = 2.3468 (The minus signs cancelled out)

Then, round pOH value to the nearest hundredth: pOH is 2.35

Thus, the poH of a 4.5 x 10-3 M OH solution is 2.35

10.25

Explanation:

on edge

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2