How many joules are absorbed when 86.8 grams of water is heated from 40.0 degrees C to 86.0 degrees C?
a) 11,400 joules
b) 12,600 joules
c) 14,100 joules
d) 16,700 joules

The answer to your question is the letter d) 16700 joules

Explanation:

Data

mass = m = 86.8 g

temperature 1 = T1 = 40°C

temperature 2 = T2 = 86°C

heat capacity = 4.18 J/g°C

Process

1.- Write the formula to calculate Heat (Q)

        Q = mC(T1 - T2)

2.- Substitution

        Q = (86.8)(4.18)(86 - 40)

3.- Simplification

        Q = (86.8)(4.18)(46)

4.- Result

         Q = 16689.9 Joules ≈ 16700 joules

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )