Write a molecular equation for the precipitation reaction that occurs. lithium sulfide and strontium iodide. potassium and sodium phosphate.

Answer;

Li2S (aq) + SrI2 (aq) > LiI2 (aq) + SrS (s)

Explanation;

-The precipitate is strontium sulfide. Lithium Iodide will be left in aqueous solution. A precipitation reaction refers to the formation of an insoluble salt (which is the precipitate) when two solutions containing soluble salts are combined.

Second case;

Potassium and sodium phosphate;

No precipitation reaction occurs -because all of the possible products of reaction will remain in aqueous solution.

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

hypostyle hall;